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(2(5/2x)-1)^2+3=7
We move all terms to the left:
(2(5/2x)-1)^2+3-(7)=0
Domain of the equation: 2x)-1)^2!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(2(+5/2x)-1)^2+3-7=0
We add all the numbers together, and all the variables
(2(+5/2x)-1)^2-4=0
We multiply all the terms by the denominator
(2(+5-4*2x)-1)^2=0
We add all the numbers together, and all the variables
(2(-4*2x+5)-1)^2=0
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